I thought it might be interesting to occasionally share something that I've learned as I work with my students. Because I teach (and I use that term loosely) several different subjects, I am always being reminded of things that I remember learning when I was in school, or I am constantly learning new concepts or new ways to teach concepts.
So, this is the problem for the day. This comes from some Algebra 3 work that a student and I worked through today. Read slowly and this is totally doable!!
Find 2 consecutive natural numbers such that the difference of their reciprocals is 1/4 the reciprocal of the smaller number!!!
Let me know what you get!!
6 comments:
That was SO easy! :) Ok, not easy, but fun!
i wish i could speak algebra. i SO don't understand what you are asking.
are you speaking english???
What the heck is Algebra 3??? I only took 1 and 2!!!
3 and 4
1/3-1/4=1/12 which is 1/4 of the reciprocal (1/3) of the smaller number 3
EASY STUFF!
Gabino
Ahhh Gabino....should have known it would be easy stuff for you!!
Ever think about being a math teacher??!!
:)
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